Find the Value of cos(7pi/2) | Cos 7π/2 Value

The value of cos(7pi/2) is equal to 0. Cos(7pi/2) is the value of cosine trigonometric function for 7π/2 radians. The formula of cos 7π/2 is given by $\boxed{\cos \dfrac{7\pi}{2} = 0}.$ Note that What is the Value of Cos 7pi/2? Answer: cos(7π/2) is equal to 0. Explanation: Note that 7π/2 can be written as follows. … Read more

Find the Value of cos(5pi/2) | Cos 5π/2 Value

The value of cos(5pi/2) is equal to 0. The formula of cos(5π/2) is given by $\boxed{\cos \dfrac{5\pi}{2} = 0}.$ Cos(5pi/2) is the value of cosine trigonometric function for 5π/2 radians. Note that What is the Value of Cos 5pi/2? Answer: cos(5π/2) is equal to 0. Explanation: Note that 5π/2 can be written as follows. $\dfrac{5\pi}{2}=2\pi … Read more

Sec2x Identity | Sec2x Formula

The sec2x identity is given by sec 2x = (sec2x cosec2x) / (cosec2x – sec2x). That is, the formula of sec2x is equal to sec 2x = $\dfrac{\sec^2x \cdot \text{cosec}^2x}{\text{cosec}^2x – \sec^2x}$ Now, let us learn how to find the sec2x identity Identity of sec2x Question: What is the identity of sec2x? Answer: The sec2x … Read more

Find the Value of sin(3pi/2) | Sin 3π/2 Value

The value of sin(3pi/2), that is, sin 270° is equal to -1. So the formula of sin(3π/2) is given by sin $\frac{3\pi}{2}$ = -1. Here we will learn how to find the value of sin 3pi/2. Note that Sin 3pi/2 Value Question: What is the value of sin(3pi/2)? Answer: sin(3π/2) is equal to -1. Explanation: … Read more

Limit of cos(1/x) as x approaches 0

The limit of cos(1/x) as x approaches 0 does not exist. In this post, we will learn how to find the limit of cos(1/x). limx→0 cos(1/x) Does Not Exist. Limit of cos(1/x) when x→0 Question: What is the limit cos(1/x) when x tend to 0? Answer: The limit of cos(1/x) does not exist when x tends … Read more

Limit x→0 sinx/x: Formula, Proof | Lim x→0 sinx/x =1 Proof

The limit of sinx/x as x approaches 0, is equal to 1. That is, the limit formula of sinx/x when x→0 is given as follows: limx→0 sinx/x = 1. In this post, we will learn how to find the limit of sinx/x when x approaches 0. Limit of sinx/x as x→0 by l’Hopital’s Rule Question: … Read more

Limit of cos(1/x) as x approaches infinity

The limit of cos(1/x) as x approaches infinity is equal to 1. The limx→∞ cos(1/x) formula is given as follows: $\lim\limits_{x \to \infty} \cos \big(\dfrac{1}{x} \big)=1$. In this post, we will learn how to prove the limit of cos(1/x) when x tends to ∞. Limx→∞ cos(1/x) Question: What is the limit of cos(1/x) when x … Read more

Limit of (1+1/n)^n as n approaches infinity

The limit of (1+1/n)^n as n approaches infinity is equal to e. The limn→∞ (1+1/n)n formula is given by $\lim\limits_{n \to \infty} \big(1+\dfrac{1}{n} \big)^n=e$. That is, the limit of (1+1/x)x when x→∞ is equal to e. In this post, we will learn to prove the limit of log(1+x)/x when x tends to zero. Limn→∞ (1 … Read more

Limit of sin(√x)/x as x approaches 0

The limit of sin(√x)/x as x approaches 0 DOES NOT exist, that is, the limx→0 sin(\sqrt{x})/x formula is given by $\lim\limits_{x \to 0} \dfrac{\sin \sqrt{x}}{x}=$ not exist. Let us learn how to find the limit of sin root x divided by x when x tends to 0. Find Limit of sin(√x)/x when x→0 We have … Read more

Limit of sin(x^2)/x as x approaches 0

The limit of sin(x^2)/x as x approaches 0 is equal to 0. The limx -> 0 sin(x2)/x formula is given by $\lim\limits_{x \to 0} \dfrac{\sin x^2}{x}=0$. Let us learn how to find the limit of sin x square divided by x when x tends to 0. Limx → 0 sin(x2)/x We have $\lim\limits_{x \to 0} … Read more