Derivative of e^3x by first principle and chain rule

The derivative of e3x is 3e3x. The function e^3x is an exponential function with an exponent 3x. In this note, we will find the derivative of e to the power 3x by the first principle of derivatives and by the chain rule of derivatives.

Derivative of e^3x

Derivative of e^3x using first principle

As we know that the derivative of a function f(x) by first principle is the below limit

ddx(f(x)) =limh0f(x+h)f(x)h,

so taking f(x)=e3x in the above equation, the derivative of e3x from first principle is

ddx(e3x) =limh0e3(x+h)e3xh

=limh0e3x+3he3xh

=limh0e3xe3he3xh

=limh0e3x(e3h1)h

=e3xlimh0e3h13h ×3

Let t=3h. Thus t0 when h0.

So from above, we get =e3xlimt0et1t ×3

=e3x×1×3 as the limit of (et1)/t is one when t tends to zero.

=3e3x

Thus the derivative of e3x is 3e3x and this is obtained by the first principle of derivatives.

Now we will find the derivative of e to the power 3x by the chain rule of derivatives.

Derivative of e^3x by Chain Rule

Let z=3x. Therefore, we have dz/dx=3. By the chain rule of derivatives, we have

ddx(e3x) =ddz(ez)dzdx

=ez3 as the derivative of ez with respect to z is ez, and dz/dx=3.

=3ez

=3e3x as z=3x

So the derivative of e^3x is 3e^3x and this is obtained by the chain rule of derivatives.

Question Answer on Derivative of e^3x

Question 1: Find the derivative of e^3.

Answer:

Note that e3 is a constant number as the number e is a constant. We know that the derivative of a constant is zero (see the page on Derivative of a constant is 0). Thus we can say that the derivative of e cube is zero.

Also Read:

Derivative of log(sin x) from first principle

Derivative of e^2x from first principle

Derivative of root(1+x) from first principle

Derivative of log(cos x) from first principle

Derivative of root sin x from first principle

Derivative of root cos x from first principle

FAQs

Q1: What is the Derivative of e^3x?

Answer: The derivative of e^3x is 3e^3x.

Spread the love
WhatsApp Group Join Now
Telegram Group Join Now