The derivative of ln3x is equal to 1/x, where ln denotes the natural logarithm. Here we will find the derivative of ln(3x).
The ln3x differentiation formula is given below:
$\dfrac{d}{dx}(\ln 3x)=\dfrac{1}{x}$.
ln(3x) Derivative
Question: Find the derivative of ln3x.
Solution:
By the logarithm rule for products,
ln 3x = ln3 + lnx.
So, $\dfrac{d}{dx}(\ln 3x)$ = $\dfrac{d}{dx}(\ln 3) + \dfrac{d}{dx}(\ln x)$, by the sum rule of differentiation.
= $0 +\dfrac{1}{x}$, as the derivative of a constant is 0 and ln3 is a constant. Also, the derivative of lnx is 1/x.
= $\dfrac{1}{x}$.
So the derivative of ln3x is equal to 1/x.
You can read: Derivative of 1/x
What is the derivative of 1/lnx?
Derivative of ln3x by Chain Rule.
Let z=3x.
So dz/dx=3.
Now, by the chain rule,
$\dfrac{d}{dx}(\ln 3x)$ = $\dfrac{d}{dz}(\ln z) \times \dfrac{dz}{dx}$
= $\dfrac{1}{z} \times 3$
= $\dfrac{3}{3x}$
= 1/x.
Therefore, the derivative of ln3x is equal to 1/x, and it is obtained by the chain rule of differentiation.
More Reading: How to find the derivative of 1/sinx?
FAQs
Q1: What is the derivative of ln3x?
Answer: The derivative of ln3x is 1/x.
Q2: If y=ln3x, then find dy/dx.
Answer: If y=ln3x, then dy/dx =1/x.