The integration of fourth root of x is 4x5/4/5 + C. In this post, we will find the integral of the fourth root of x by the power rule of integration.
Let us now learn how to integrate fourth root x.
Integral of Fourth Root of x
The fourth root of x is expressed as follows: $\sqrt[4]{x}$ which can be further rewrite by the rule of indices as $x^{\frac{1}{4}}$.
That is, $\sqrt[4]{x}=x^{\frac{1}{4}}$ …(I)
As fourth root of x is a power of x, we can use the power rule of integration to find its integral. By the power rule of integration, we have
∫xn dx = xn+1/(n+1) + C where C is a constant of integration.
Putting n=1/4, we get the integral of fourth root of x as follows:
∫x1/4 dx = $\dfrac{x^{\frac{1}{4} +1}}{\frac{1}{4}+1}$ + C
⇒ ∫$\sqrt[4]{x}$ dx = $\dfrac{x^{5/4}}{5/4}$ + C
⇒ ∫$\sqrt[4]{x}$ dx = $\dfrac{4}{5}x^{5/4}$ + C
So the integration of fourth root of x is 4x5/4/5 + C where C denotes an integral constant, and this is proved by the power rule of integration.
Read These
Question 1: Find the definite integral of fourth root of x from 0 to 1, that is Find ∫$_0^1$x1/4 dx? |
Solution:
From above we have that the integration of fourth root of x is 4x5/4/5 + C. Therefore,
∫$_0^1$ x1/4 dx
= [4x5/4/5 + C]$_0^1$
= (4 ⋅ 15/4/5 + C) – (4 ⋅ 05/4/5 + C)
= 4/5+C – 0 -C
= 4/5.
So the integration of fourth root of x from 0 to 1 is equal to 4/5.
Question 2: What is the integration of 4? |
Solution:
As 4 is a constant function of x, the integration of 4 with respect to x will be equal to
∫ 4 dx
= 4∫dx
= 4x + C.
So the integration of 4 is equal to 4x+C.
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FAQs
Q1: What is the integration of fourth root x?
Answer: The integration of fourth root x is equal to 4x5/4/5 + C, that is, ∫x1/4 dx = 4x5/4/5 + C.