The integration of tanx is -ln|cosx| or ln|secx|, where ln denotes the natural logarithm, that is, logarithm with base e. Here we will learn how to find the integral of tanx dx.
tanx Integration Formula
The tanx integration formula is given below.
- ∫tanx dx = -ln|cosx|+C
- ∫tanx dx = ln|secx|+C.
Integration of tanx Proof
We will show that ∫tanx dx = -ln|cosx|+C. As $\tan x =\dfrac{\sin x}{\cos x}$, the integral of tanx will be equal to
∫tanx dx = $\int \dfrac{\sin x}{\cos x} \ dx$
Let us put cosx=z.
Differentiating, -sinx dx = dz.
So we have from above that
∫tanx dx = $\int \dfrac{-dz}{z}$
= – $\int \dfrac{dz}{z}$
= – ln|z|+C where C is a constant of integration
= -ln|cosx|+C as z=cosx.
So the integration of tanx is equal to -ln|cosx|+C (or) ln|secx|+C as secx=/cosx. This is obtained by the substitution method of integrations.
Have You Read These Integrations?
Integration of secx | Integration of cotx |
Integration of cosecx | Integration of root(x) |
Integration cube root of x | Integration of 1/√x |
Integration of 1/x | Integration of ln(x) |
Video Solution on Integration of tanx:
FAQs
Q1: What is the Integration of tanx?
Answer: The integration of tanx is -ln|cosx|+C where C is the integration constants.