The sec2x identity is given by sec 2x = (sec2x cosec2x) / (cosec2x – sec2x). That is, the formula of sec2x is equal to
sec 2x = $\dfrac{\sec^2x \cdot \text{cosec}^2x}{\text{cosec}^2x – \sec^2x}$
Now, let us learn how to find the sec2x identity
Identity of sec2x
Question: What is the identity of sec2x?
Answer: The sec2x identity is equal to sec2x = (sec2x cosec2x)/(cosec2x – sec2x).
Explanation:
Proof of sec2x Identity: As secx is the reciprocal of cosx, we have that
sec2x = $\dfrac{1}{\cos 2x}$
= $\dfrac{1}{\cos (x+x)}$
= $\dfrac{1}{\cos x \cos x -\sin x \sin x}$ as we know cos(a+b) = cosa cosb -sina sinb
= $\dfrac{1}{\cos^2 x -\sin^2 x}$
= $\dfrac{1}{\frac{1}{\sec^2 x} -\frac{1}{\text{cosec}^2 x}}$, because $\cos x=\dfrac{1}{\sec x}$ and $\sin x =\dfrac{1}{\text{cosec}x}$.
= $\dfrac{1}{\frac{\text{cosec}^2 x -\sec^2 x}{\sec^2 x \cdot \text{cosec}^2 x}}$
= $\dfrac{\sec^2 x \cdot \text{cosec}^2 x}{\text{cosec}^2 x -\sec^2 x}$
So the identity of sec2x is equal to sec2x = (sec2x cosec2x)/(cosec2x – sec2x), and this is the sec2x identity in terms of secx and cosecx.
$\boxed{\sec 2x = \dfrac{\sec^2x \cdot \text{cosec}^2x}{\text{cosec}^2x – \sec^2x}}$
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FAQs
Q1: What is the formula of sec2x?
Answer: The sec2x formula is given by sec2x = (sec2x cosec2x)/(cosec2x – sec2x).