The general solution of the differential equation dy/dx=x-y is equal to y=x-1-Ce-x where C is an arbitrary constant. In this post, we will learn how to find the general solution of dy/dx =x-y.
Solution of dy/dx=x-y
Question: Find the genral solution of $\dfrac{dy}{dx}$ =x-y.
Solution:
Let x-y=v.
Differentiating w.r.t x, we get that
$1-\dfrac{dy}{dx}=\dfrac{dv}{dx}$
⇒ $\dfrac{dy}{dx}=1-\dfrac{dv}{dx}$
So the given equation dy/dx =x-y becomes
$1-\dfrac{dv}{dx}=v$
⇒ $\dfrac{dv}{dx}=1-v$
⇒ $-\dfrac{dv}{v-1}=dx$
Integrating, $-\int \dfrac{dv}{v-1}=\int dx -K$
$-\ln |v-1|=x-K$
⇒ $\ln |v-1|=-x+K$
⇒ $v-1 =e^{-x+K}$
⇒ $x-y-1 =Ce^{-x}$ where C=eK [as v=x-y]
⇒ $y =x-1-Ce^{-x}$
So the general solution of dy/dx=x-y is equal to y=x-1-Ce-x where C denotes an integral constant.
Related Topics: How to solve dy/dx=x+y
FAQs
Q1: What is the solution of the differential equation dy/dx=x-y?
Answer: The solution of the differential equation dy/dx=x-y is given by y=x-1-Ce-x where C is a constant.